Let a, b be vectors with | a|=√14, | b|=√6, | a b|=√48.

Question

Let $\vec a,\vec b$ be vectors with $|\vec a|=\sqrt{14}$, $|\vec b|=\sqrt6$, $|\vec a	imes\vec b|=\sqrt{48}$. Then $(\vec a\cdot\vec b)^2$ is equal to \_\_\_\_\_\_\_.

Answer: 36

Accepted Answer

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