Question 146 of 379MediumMCQ
Let a=3i^+j^−2k^, b=4i^+j^+7k^, and c=i^−3j^+4k^. If a vector p satisfies p×b=c×b and p⋅a=0, then p⋅(i^−j^−k^) is equal to Solutions · 1
Official solution
(p−c)×b=0⇒p=c+λb.
p⋅a=0: c⋅a+λ(b⋅a)=0.
c⋅a=3−3−8=−8; b⋅a=12+1−14=−1: −8−λ=0⇒λ=−8.
p=c−8b=(1−32,−3−8,4−56)=(−31,−11,−52).
\[\vec p\cdot(\hat i-\hat j-\hat k) = -31+11+52 = 32\] Answer the question to unlock