The number of common tangents to the circles x2+y2−18x−15y+131=0 and x2+y2−6x−6y−7=0 is:
Solutions · 1
Official solution
C1=(9,7.5),r1=81+56.25−131=2.5. C2=(3,3),r2=9+9+7=5.
\[C_1C_2=\sqrt{36+20.25}=7.5=r_1+r_2,\]
so the circles are externally tangent, giving 3 common tangents.