Let Δ be the area of the region {(x,y)∈R2:x2+y2≤21,y2≤4x,x≥1}. Then a certain combination of Δ and 21sin−1(72) is equal to:
Solutions · 1
Official solution
The parabola and circle meet at x=3 (y=±23). Splitting the region at x=3:
\[\Delta = \int_1^3 4\sqrt x\,dx + 2\int_3^{\sqrt{21}}\sqrt{21-x^2}\,dx = \frac83(3\sqrt{3}-1) + 21\sin^{-1}\!\left(\frac{2}{\sqrt{7}}\right) - 6\sqrt{3}.\]
*(The exact combination asked for in the stem was corrupted in the source; independent computation gives Δ−21sin−1(2/7)=23−38, which does not exactly match any option --- the precise coefficient in the requested expression could not be recovered. The stated answer is option C.)*