Let A and B be the two points of intersection of the line y+5=0 and the mirror image of the parabola y2=4x with respect to the line x+y+4=0. If d denotes the distance between A and B, and a denotes the area of △SAB, where S is the focus of the parabola y2=4x, then the value of a+d is \_\_\_\_\_\_\_\_.
Answer: 14
Solutions · 1
Official solution
*(The full working for the mirror-image parabola is heavily corrupted in the source; the recoverable final steps give A,B four units apart with the triangle's base 4 and height 5.)*
\[a=\text{Area}=\frac12\times4\times5=10,\qquad d=4,\qquad a+d=14.\]