Question 275 of 298EasyMCQ
The period of sin2θ is:
Solutions · 1
Official solution
The period of \[{\sin ^2}\theta \] is = \[\pi \]
Note :
(1) When n is odd then the period of \[{\sin ^n}\theta \], \[{\cos ^n}\theta \], \[{\csc ^n}\theta \], \[{\sec ^n}\theta \] = \[2\pi \]
(2) When n is even then the period of \[{\sin ^n}\theta \], \[{\cos ^n}\theta \], \[{\csc ^n}\theta \], \[{\sec ^n}\theta \] = \[\pi \]
(3) When n is even/odd then the period of \[{\tan ^n}\theta \], \[{\cot ^n}\theta \] = \[\pi \]
(3) When n is even/odd then the period of \[\left| {{{\sin }^n}\theta } \right|\], \[\left| {{{\cos }^n}\theta } \right|\], \[\left| {{{\csc }^n}\theta } \right|\], \[\left| {{{\sec }^n}\theta } \right|\], \[\left| {{{\tan }^n}\theta } \right|\], \[\left| {{{\cot }^n}\theta } \right|\] = \[\pi \]
Answer the question to unlock