A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank. The two sides having fence are of the same length x. The maximum area enclosed by the park is:
Solutions · 1
Official solution
Area \[ = {1 \over 2}{x^2}\,\sin \,\theta \]
Maximum value of \[\sin \theta \] is 1 at \[\theta = {\pi \over 2}\]
\[{A_{\max }} = {1 \over 2}{x^2}\]