Multiplying and dividing by sin22π, and repeatedly using sinθcosθ=21sin2θ:
\[= \frac1{2}\cos\tfrac\pi{2^2}\cos\tfrac\pi{2^3}\cdots\cos\tfrac\pi{2^9}\sin\tfrac\pi{2^9} = \cdots = \frac1{2^8}\cos\tfrac\pi{2^2}\sin\tfrac\pi{2^2} = \frac1{2^9}\sin\tfrac\pi2 = \frac1{512}\]