Two poles standing on a horizontal ground are of heights 5m and 10m respectively. The line joining their tops makes an angle of 15∘ with the ground. Then the distance (in m) between the poles is:
Solutions · 1
Official solution
The vertical difference in heights is 10−5=5 m. With tan15∘=d5:
\[d = \frac5{\tan15^\circ} = \frac{5(\sqrt{3}+1)}{\sqrt{3}-1} = \frac{5(4+2\sqrt{3})}2 = 5(2+\sqrt{3})\]