The number of solutions of the equation sinx=cos2x in the interval (0,10) is \_\_\_\_\_\_\_\_\_\_\_
Answer: 4
Solutions · 1
Official solution
\[\sin x = 1-\sin^2x \implies \sin^2x+\sin x-1=0 \implies \sin x = \frac{-1\pm\sqrt{5}}2\]
Since sinx∈(−1,1), only sinx=25−1≈0.618 is valid.
Since 3π≈9.42<10 and 27π≈10.99>10, the interval (0,10) contains 3 full "humps" of sinx (i.e. extends a bit past 3π into the fourth). The horizontal line y=0.618 intersects the graph of sinx 4 times within (0,10).