Let P be the point of intersection of the common tangents to the parabola y2=12x and hyperbola 8x2−y2=8. If S and S′ denote the foci of the hyperbola, where S lies on the positive x-axis, then P divides SS′ in a ratio:
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Official solution
Parabola: a=3, tangent y=mx+m3. Hyperbola x2−8y2=1: tangent y=mx+c, c2=m2−8.
\[\left(\frac3m\right)^2=m^2-8\Rightarrow9=m^4-8m^2\Rightarrow(m^2-9)(m^2+1)=0\Rightarrow m^2=9.\]
Tangents: y=3x+1 and y=−3x−1; intersection P=(−31,0).
S=(3,0), S′=(−3,0): S′P=38, PS=310, so P divides SS′ in ratio SP:PS′=10:8=5:4.