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Exams
Joint Entrance Examination
Mathematics
Trigonometric Ratios and Identities
Question 126
Question 126 of 298
Medium
MCQ
The equation of a tangent to the hyperbola
4
x
2
−
5
y
2
=
20
4x^2-5y^2=20
4
x
2
−
5
y
2
=
20
parallel to the line
x
−
y
=
2
x-y=2
x
−
y
=
2
is:
A
x
−
y
+
1
=
0
x-y+1=0
x
−
y
+
1
=
0
B
x
−
y
+
7
=
0
x-y+7=0
x
−
y
+
7
=
0
C
x
−
y
+
9
=
0
x-y+9=0
x
−
y
+
9
=
0
D
x
−
y
−
3
=
0
x-y-3=0
x
−
y
−
3
=
0
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Solutions · 1
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Official solution
x
2
5
−
y
2
4
=
1
\dfrac{x^2}5-\dfrac{y^2}4=1
5
x
2
−
4
y
2
=
1
; tangent with slope
m
=
1
m=1
m
=
1
:
y
=
x
±
a
2
m
2
−
b
2
=
x
±
5
−
4
=
x
±
1
y=x\pm\sqrt{a^2m^2-b^2}=x\pm\sqrt{5-4}=x\pm1
y
=
x
±
a
2
m
2
−
b
2
=
x
±
5
−
4
=
x
±
1
.
x
−
y
+
1
=
0.
x-y+1=0.
x
−
y
+
1
=
0.
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