The combined equation of the two lines ax+by+c=0 and a′x+b′y+c′=0 can be written as
(ax+by+c)(a′x+b′y+c′)=0.
The equation of the angle bisectors of the lines represented by the equation 2x2+xy−3y2=0 is :
Solutions · 1
Official solution
For pair of straight lines in this form
ax2+by2+2hxy+2gx+2fy+c=0
Equation of angle bisector is
\[
\frac{x^2-y^2}{a-b}=\frac{x y}{h}
\]
for 2x2+xy−3y2=0
\[
a=2, b=-3, h=\frac{1}{2}
\]
Equation of angle bisector is
\[
5x2−y2=1/2xy⇒x2−y2−10xy=0
\]