If the point (1,a) lies between the straight lines x+y=1 and 2(x+y)=3 then a lies in inter…

Question

If the point $(1,a)$ lies between the straight lines $x+y=1$ and $2(x+y)=3$ then $a$ lies in interval:

Accepted Answer

At $x=1$: $x+y=1 \implies y=0$; $2(x+y)=3\implies y=\dfrac12$.

For $(1,a)$ to lie between these lines: $a\in\left(0,\dfrac12\right)$.

Solutions · 1