A ray of light along x+√3y=√3 gets reflected upon reaching x-axis, the equation of the ref…

Question

A ray of light along $x+\sqrt3y=\sqrt3$ gets reflected upon reaching $x$-axis, the equation of the reflected ray is:

Accepted Answer

The incident ray meets the $x$-axis at $(\sqrt3,0)$. Take another point on the incident ray, $B(0,1)$; its reflection is $B'(0,-1)$.

The reflected ray passes through $A(\sqrt3,0)$ and $B'(0,-1)$: slope $=\dfrac{-1-0}{0-\sqrt3}=\dfrac1{\sqrt3}$:
$$y-0=\frac1{\sqrt3}(x-\sqrt3) \implies \sqrt3y=x-\sqrt3$$

Solutions · 1