A light ray emerging from the point source placed at P(1,3) is reflected at a point Q in the axis of x. If the reflected ray passes through the point R(6,7), then the abscissa of Q is:
Solutions · 1
Official solution
Reflecting P(1,3) in the x-axis gives P′(1,−3); the reflected ray is the line P′R:
\[\text{slope} = \frac{7-(-3)}{6-1}=2\]
Line: y+3=2(x−1); at y=0: x=25.