The image of the point (3,5) in the line x-y+1=0, lies on:

Question

The image of the point $(3,5)$ in the line $x-y+1=0$, lies on:

Accepted Answer

So, let the image is (x, y)

So, we have

$${{x - 3} \over 1} = {{y - 5} \over { - 1}} =  - {{2(3 - 5 + 1)} \over {1 + 1}}$$

$$ \Rightarrow $$ x = 4, y = 4

$$ \Rightarrow $$ Point (4, 4)

Which will satisfy the curve

(x - 2)2 + (y - 4)2 = 4

as (4 - 2)2 + (4 - 4)2 = 4 + 0 = 4

Solutions · 1