Among the statements
(S1) : If A(5,−1) and B(−2,3) are two vertices of a triangle, whose orthocentre is (0,0), then its third vertex is (−4,−7)
and
(S2) : If positive numbers 2a,b,c are three consecutive terms of an A.P., th...
Solutions · 1
Official solution
mAOmBC=−1⇒2h−3k=13……mABmOC=−1⇒4k=7h………….
\Rightarrow third vertex is (−4,−7)
Solution of statement -2
2a,b,c→A⋅Pb=22a+c⇒2a−2b+c=0
\therefore lines ax+by+c=0 are concurrent then
2x=−2y=11x=2y=−2∴Pt. Of concurrency is (2,−2)
\therefore Statement 2 is correct.