Let in a series of 2n observations, half of them are equal to a and remaining half are equal to −a. Also, by adding a constant b in each of these observations, the mean and standard deviation of new set become 5 and 20, respectively. Then, the value of a2+b2 is equal to
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Official solution
Mean of original (before adding b): xˉ=0 (equal numbers of +a and −a).
\[\sigma_x^2 = \frac{a^2\times2n}{2n} = a^2 \implies \sigma_x=a\]
After adding constant b: new mean =0+b=5⟹b=5; new S.D. =σx=20⟹a=20.
a2+b2=400+25=425