If the mean of the frequency distribution is 28, then its variance is \_\_\_\_\_\_\_.
Answer: 151
Solutions · 1
Official solution
Let the class marks with an unknown frequency variable x give: xˉ=14+x10+45+25x+175+130=28
\[28(14+x) = 410+25x \implies 392+28x = 410+25x \implies 3x=18 \implies x=6\]
\[\text{Variance} = \frac{1}{N}\sum f_ix_i^2-(\bar x)^2 = \frac{18700}{20}-(28)^2 = 935-784 = 151\]