Question 7 of 208MediumMCQ
Suppose that the mean and median of the non-negative numbers 21,8,17,a,51,103,b,13,67,(a>b), are 40 and 21 , respectively. If the mean deviation about the median is 26 , then 2a is equal to :
Solutions · 1
Official solution
The given data set has n=9 observations: 21,8,17,a,51,103,b,13,67.
The mean (x) of these numbers is given as 40.
The formula for the mean is:
=n
Substitute the given values into the formula:
40=921+8+17+a+51+103+b+13+67
Multiply both sides by 9:
360=280+a+b
a+b=360−280
a+b=80
The median (M) of the data is 21. For n=9 (an odd number), the median is the (29+1)=5 observation when aligned in ascending order.
Let's arrange the known numbers in ascending order:
8,13,17,21,51,67,103
Here, there are exactly three numbers less than 21 (8,13,17) and three numbers greater than 21 (51,67,103).
For 21 to remain the middle (5th) observation among all 9 numbers, one of the unknown variables (a or b) must be less than or equal to 21, and the other must be greater than or equal to 21.
Since it is given that a>b, we can conclude:
a≥21 and b≤21
The formula for mean deviation about the median is:
=n∑ni=1∣xi−M∣
We are given that =26.
Substitute the values:
26=9∣21−21∣+∣8−21∣+∣17−21∣+∣a−21∣+∣51−21∣+∣103−21∣+∣b−21∣+∣13−21∣+∣67−21∣
Multiply by 9 and simplify the absolute values for the known numbers:
234=0+13+4+∣a−21∣+30+82+∣b−21∣+8+46
234=183+∣a−21∣+∣b−21∣
∣a−21∣+∣b−21∣=234−183
∣a−21∣+∣b−21∣=51
From Step 2, we know that a≥21⟹∣a−21∣=a−21 and b≤21⟹∣b−21∣=21−b. Replacing these in the equation:
(a−21)+(21−b)=51
a−b=51
Now we have a system of two linear equations:
1) a+b=80
2) a−b=51
To find 2a, simply add Equation 1 and Equation 2:
(a+b)+(a−b)=80+51
2a=131
Therefore, the value of 2a is 131.
Option D is the correct answer.
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