Question 59 of 208MediumMCQ
The mean deviation about the mean for the data
xi, 5, 7, 9, 10, 12, 15 |
---|---|---|---|---|---|---|
fi, 8, 6, 2, 2, 2, 6 |
is equal to: Solutions · 1
Official solution
\[\sum f_i = 8+6+2+2+2+6 = 26, \qquad \sum f_ix_i = 40+42+18+20+24+90 = 234\]
\[\bar{x} = \frac{234}{26} = 9\]
, xi, fi, ∥xi−9∥, fi∥xi−9∥ |
---|---|---|---|
5, 8, 4, 32 |
7, 6, 2, 12 |
9, 2, 0, 0 |
10, 2, 1, 2 |
12, 2, 3, 6 |
15, 6, 6, 36 |
\[\sum f_i|x_i-\bar{x}| = 32+12+0+2+6+36 = 88\]
\[\text{M.D.} = \frac{88}{26} = \frac{44}{13}\] Answer the question to unlock