Question 24 of 208MediumMCQ
If the variance of the frequency distribution
x
c
2c
3c
4c
5c
6c
f
2
1
1
1
1
1
is 160, then the value of c∈N is Solutions · 1
Official solution
xi
f(xi)
x(f(x)
x2f(x)
C
2
2C
2C2
2C
1
2C
4C2
3C
1
3C
9C2
4C
1
4C
16C2
5C
1
5C
25C2
6C
1
6C
36C2
σ2=E(x2)−[E(x)],∑f(xi)=7E(x)=∑xf(x)=22CE(x2)=∑x2f(x)=92C2
σ2=160=792C2−(722C)2⇒C=±7C∈N⇒C=7 Answer the question to unlock