Official solution
\[\because\] \[\overline x = 6 = {{a + b + 8 + 5 + 10} \over 5} \Rightarrow a + b = 7\] ...... (i)
And \[{\sigma ^2} = {{{a^2} + {b^2} + {8^2} + {5^2} + {{10}^2}} \over 5} - {6^2} = 6.8\]
\[ \Rightarrow {a^2} + {b^2} = 25\] ..... (ii)
From (i) and (ii) (a, b) = (3, 4) or (4, 3)
Now mean deviation about mean
\[M = {1 \over 5}(3 + 2 + 2 + 1 + 4) = {{12} \over 5}\]
\[ \Rightarrow 25M = 60\]