Official solution
\[{\sigma ^2} = {{\sum {x_i^2} } \over {10}} - {\left( {{{\sum {{x_i}} } \over {10}}} \right)^2} \to (i)\]
Now x1 + x2 + x3 + x4 = 44 \& x5 + x6 + ......... + x10 = 96
Hence \[{\sigma ^2}\] = \[{{2000} \over {10}} - {\left( {{{140} \over {10}}} \right)^2}\] = 200 - 196 = 4
Hence \[\sigma \] = 2