Question 83 of 161MediumMCQ
If A = {x∈R:∣x∣<2} and B = {x∈R:∣x−2∣≥3}; then: Solutions · 1
Official solution
A=(−2,2). For B: ∣x−2∣≥3⟹x≥5 or x≤−1, so B=(−∞,−1]∪[5,∞).
\[A\cap B = (-2,2)\cap\big[(-\infty,-1]\cup[5,\infty)\big] = (-2,-1]\]
\[A\cup B = (-2,2)\cup(-\infty,-1]\cup[5,\infty) = (-\infty,2)\cup[5,\infty)\]
\[A-B = (-2,2)\cap(-1,5) = (-1,2)\]
\[B-A = \big[(-\infty,-1]\cup[5,\infty)\big]\cap\big[(-\infty,-2]\cup[2,\infty)\big] = (-\infty,-2]\cup[5,\infty) = \mathbb R-(-2,5)\]
Option B is correct: B−A=R−(−2,5). Answer the question to unlock