Let P and Q be two distinct points on a circle which has centre C(2,3) and which passes through the origin O. If OC is perpendicular to both the line segments CP and CQ, then the set {P,Q} is equal to
Solutions · 1
Official solution
r=OC=13. P,Q lie on the circle along the line through C perpendicular to OC=(2,3), at distance r from C: unit perpendicular (∓133,±132).
\[P=(2,3)+\sqrt{13}\left(-\frac3{\sqrt{13}},\frac2{\sqrt{13}}\right)=(-1,5),\qquad Q=(2,3)+\sqrt{13}\left(\frac3{\sqrt{13}},-\frac2{\sqrt{13}}\right)=(5,1).\]