Let \[A=\{2,3,6,8,9,11\}\] and \[B=\{1,4,5,10,15\}\]. Let R be a relation on \[A \times B\] defined by
(a,b)R(c,d) if and only if 3ad−7bc is an even integer. Then the relation R is
Solutions · 1
Official solution
\[(a, b) R(c, d) \Rightarrow 3 a d-7 b c \in\] even
For reflexive
\[(a, b) R(a, b) \Rightarrow 3 a b-7 b a=-4 a b \in\] even
For symmetric
(a,b)R(c,d)
then
(c,d)R(a,b)=3bc−7ad
\[\in\] even
Now check for transitive
\[\[(a,b)R(c,d) and (c,d)R(e,f) then (a,b)R(e,f)3ad−7bc=2m⇒(2,5)R(6,8) and 3cf−7ed=2n(6,8)R(9,4) then 3af−7eb= even ∈/(2,5)R(9,4)⇒ Not transitive option (3)\]
\]