Let \[\mathrm{R}\] be a relation on \[\mathrm{N} \times \mathbb{N}\] defined by \[(a, b) ~\mathrm{R}~(c, d)\] if and only if ad(b−c)=bc(a−d). Then \[\mathrm{R}\] is
Solutions · 1
Official solution
Given, (a,b)R(c,d)⇒ad(b−c)=bc(a−d)
Symmetric :
(c, d) R(a,b)⇒cb(d−a)=da(c−b)⇒ Symmetric.
Reflexive :
(a, b) R (a, b) ⇒ab(b−a)=ba(a−b)⇒ Not reflexive.
Transitive :
(2,3)R(3,2) and (3,2)R(5,30) but
((2,3),(5,30))∈/R⇒ Not transitive.