Let R = (P, Q), P and Q are at the same distance from the origin be a relation, then the e…

Question

Let R = {(P, Q), P and Q are at the same distance from the origin} be a relation, then the equivalence class of (1, -1) is the set :

Accepted Answer

Given R = {(P, Q), P and Q are at the same distance from the origin}.

Then equivalence class of (1, -1) will contain al such points which lies on circumference of the circle of centre at origin and passing through point (1, -1).

i.e., radius of circle = $$\sqrt {{1^2} + {1^2}}  = \sqrt 2 $$

$$ \therefore $$ Required equivalence class of (S)

$$ = \{ (x,y)|{x^2} + {y^2} = 2\} $$.

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