Let R1 and R2 be two relations defined on R by aR1b⟺ab≥0 and aR2b⟺a≥b. Then:
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Official solution
R1: Reflexive (x⋅x=x2≥0). Symmetric (xy≥0⟺yx≥0). Not transitive: x=2,y=0,z=−2 gives xy=0≥0, yz=0≥0, but xz=−4<0. So R1 is not an equivalence relation.
R2: a≥b does not imply b≥a --- not symmetric. So R2 is not an equivalence relation.
Neither is an equivalence relation.