Official solution
\[x = \sum\limits_{n = 0}^\infty {{a^n} = {1 \over {1 - a}};\,y = \sum\limits_{n = 0}^\infty {{b^n} = {1 \over {1 - b}};\,z = \sum\limits_{n = 0}^\infty {{c^n} = {1 \over {1 - c}}} } } \]
Now,
a, b, c \[\to\] AP
1 - a, 1 - b, 1 - c \[\to\] AP
\[{1 \over {1 - a}},\,{1 \over {1 - b}},\,{1 \over {1 - c}} \to HP\]
x, y, z \[\to\] HP
\[\therefore\] \[{1 \over x},{1 \over y},{1 \over z} \to AP\]