Official solution
Sum of infinite G.P,
S = \[b \over {1-r}\] where \[\left| r \right| < 1\]
\[ \Rightarrow \] 5 = \[b \over {1-r}\]
\[ \Rightarrow \] 1 - r = \[b \over 5\]
\[ \Rightarrow \] b = 5(1 - r)
as \[\left| r \right| < 1\]
\[ \therefore \] -1 < r < 1
\[ \Rightarrow \] 1 > -r > -1
\[ \Rightarrow \] 2 > 1-r > 0
\[ \Rightarrow \] 10 > 5(1-r) > 0
\[ \Rightarrow \] 10 > b > 0
\[ \therefore \] interval of b = (0, 10)