The number of terms of an A.P. is even; the sum of all the odd terms is 24 , the sum of all the even terms is 30 and the last term exceeds the first by 221. Then the number of terms which are integers in the A.P. is :
Solutions · 1
Official solution
Let the number of terms be 2n
\[nd=6(a+(2n+1)d)−a=221⇒2nd−d=221⇒12−221=d\]
\[⇒d=23∴n=4∴ Total terms =8\]