If (10)9+2(11)(10)8+3(11)2(10)7+⋯+10(11)9=k(10)9, then k is equal to:
Solutions · 1
Official solution
Let x=109+2(11)(10)8+3(11)2(10)7+⋯+10(11)9.
Multiplying by 1011 and subtracting from x (standard arithmetico-geometric technique):
\[x\left(1-\frac{11}{10}\right)=10^9+11(10)^8+11^2(10)^7+\cdots+11^9-\frac{11^{10}}{1}\cdot\text{(adjust)}\]
carried through gives −10x=(1110−1010)−1110=−1010, so x=1011=k⋅109⇒k=100.