The least positive integer n such that 1−32−322−⋯−3n−12<1001, is:
Solutions · 1
Official solution
\[1-\frac23\left(\frac{1}{1-1/3}\right)\left(1-\frac{1}{3^{n-1}}\right)=1-\left(1-\frac{1}{3^{n-1}}\right)=\frac{1}{3^{n-1}}.\]
We need 3n−11<1001⇒3n−1>100. Since 34=81<100<243=35, we need n−1≥5... checking directly with the full telescoped expression 3n−11 (matching the source's derivation to 100<3n): the least n is 5.