If the 19th term of a nonzero A.P.

Question

If the $19$th term of a nonzero A.P. is zero, then its (49th term):(29th term) is:

Accepted Answer

$t_{19}=a+18d=0 \Rightarrow a=-18d$.

$$\frac{t_{49}}{t_{29}} = \frac{a+48d}{a+28d} = \frac{30d}{10d} = 3 \implies 3:1.$$

Solutions · 1