The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the G.P. is:
Solutions · 1
Official solution
Let terms are \[{a \over r},a,ar \to G.P\]
\[ \therefore \] a3 = 512 \[ \Rightarrow \] a = 8
\[{8 \over r} + 4,12,8r \to A.P.\]
24 = \[{8 \over r} + 4 + 8r\]
r = 2, r = \[{1 \over 2}\]
r = 2(4, 8, 16)
r = \[{1 \over 2}\] (16, 8, 4)
Sum = 28