Let 3,6,9,12,… up to 78 terms and 5,9,13,17,… up to 59 terms be two series. Then the sum of the terms common to both series is equal to \_\_\_\_\_\_\_\_.
Answer: 2223
Solutions · 1
Official solution
Last terms: t78=234 (first AP), t59=237 (second AP).
Common terms form an A.P. with first term 9 and common difference lcm(3,4)=12: 9,21,33,…≤234, giving n≤12237⇒n=19.
\[S_{19} = \frac{19}{2}\big[2(9)+18(12)\big] = 19(9+108) = 2223.\]