Let \[S=109+\frac{108}{5}+\frac{107}{5^{2}}+\ldots .+\frac{2}{5^{107}}+\frac{1}{5^{108}}\]. Then the value of \[\left(16 S-(25)^{-54}\right)\] is equal to \_\_\_\_\_\_\_\_\_\_\_.
Answer: 2175
Solutions · 1
Official solution
We have, S=109+5108+52107+…+51072+51081 ...........(i)
5S=5109+52108+53107+….+51082+51091 .............(ii)
On subtracting Eq. (ii) from Eq. (i), we get
\begin{gathered} \frac{4S}{5} =109-\frac{1}{5}-\frac{1}{{5}^{2}}-\ldots .-\frac{1}{{5}^{108}}-\frac{1}{{5}^{109}} \\ \\ \frac{4S}{5} =109-[\frac{1}{5}+\frac{1}{{5}^{2}}+\ldots +\frac{1}{{5}^{108}}+\frac{1}{{5}^{109}}]
This form a GP with r=51 \frac{4S}{5} =109-\frac{1}{5}[\frac{1-\frac{1}{{5}^{109}}}{1-\frac{1}{5}}] \\ \\ =109-\frac{1}{4}[1-\frac{1}{{5}^{109}}] \\ \\ =109-\frac{1}{4}+\frac{1}{4}\times \frac{1}{{5}^{109}} \end{gathered}∴4S=45[435+51091]⇒16S=2175+5108116S−(25)−54=2175