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Joint Entrance Examination
Mathematics
Quadratic Equations and Inequalities
Question 89
Question 89 of 157
Medium
MCQ
If both the roots of the quadratic equation
x
2
−
2
k
x
+
k
2
+
k
−
5
=
0
{x^2} - 2kx + {k^2} + k - 5 = 0
x
2
−
2
k
x
+
k
2
+
k
−
5
=
0
are less than 5, then
k
k
k
lies in the interval
A
\[\left( {5,6} \right]\]
B
\[\left( {6,\,\infty } \right)\]
C
\[\left( { - \infty ,\,4} \right)\]
D
\[\left[ {4,\,5} \right]\]
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Official solution
both roots are less than
5
,
5,
5
,
then
(
i
)
(i)
(
i
)
Discriminant \[ \ge 0\] \[\left( {ii} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,p\left( 5 \right) > 0\] \[\left( {iii} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{Sum\,\,of\,\,roots} \over 2} < 5\] Hence \[\left( i \right)\,\,\,\,\,\,4{k^2} - 4\left( {{k^2} + k - 5} \right) \ge 0\] \[4{k^2} - 4{k^2} - 4k + 20 \ge 0\] \[4k \le 20 \Rightarrow k \le 5\] \[\left( {ii} \right)\,\,\,\,\,f\left( 5 \right) > 0;25 - 10k + {k^2} + k - 5 > 0\] or
k
2
−
9
k
+
20
>
0
{k^2} - 9k + 20 > 0
k
2
−
9
k
+
20
>
0
or \[k\left( {k - 4} \right) - 5\left( {k - 4} \right) > 0\] or \[\left( {k - 5} \right)\left( {k - 4} \right) > 0\] \[ \Rightarrow k \in \left( { - \infty ,4} \right) \cup \left( { - \infty ,5} \right)\] \[\left( {iii} \right)\,\,\,\,\,\,{{Sum\,\,of\,\,roots} \over 2}\] \[ = - {b \over {2a}} = {{2k} \over 2} < 5\] The intersection of
(
i
)
(i)
(
i
)
,
(
i
i
)
(ii)
(
ii
)
\&
(
i
i
i
)
(iii)
(
iii
)
gives \[k \in \left( { - \infty ,4} \right).\]
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