Question 62 of 157MediumNUMERICAL
The number of real solutions of the equation x∣x+5∣+2∣x+7∣−2=0 is \_\_\_\_\_\_\_\_\_\_.
Answer: 3 Solutions · 1
Official solution
x∣x+5∣+2∣x+7∣−2=0
dx≥−5⇒x(x+5)+2(x+7)−2=0x2+7x+12=0⇒x=−3,−4
\begin{gathered} \, x\in (-7,-5) \\ x(-x-5)+2(x+7)-2=0 \\ -{x}^{2}-3x+12=0 \\ \Rightarrow {x}^{2}+3x-12=0 \\ \Rightarrow x=\frac{-3-\sqrt{57}}{2}
\, x\le -7 \\ \Rightarrow x(-x-5)+2(-x-7)-2=0 \\ -{x}^{2}-7x-16=0\Rightarrow {x}^{2}+7x+16=0 \end{gathered}
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