The number of solutions of the equation
(x9−x9+2)(x2−x7+3)=0 is :
Solutions · 1
Official solution
Let α=x1 (x>0). Then x1=α2, and the equation becomes
\[(9\alpha^2-9\alpha+2)(2\alpha^2-7\alpha+3)=0 \implies (3\alpha-2)(3\alpha-1)(\alpha-3)(2\alpha-1)=0\]
\[\alpha = \frac13, \frac12, \frac23, 3\]
Correspondingly, x=α21=9,4,49,91 --- all four values are valid (x>0).
Number of solutions = 4.