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Joint Entrance Examination
Mathematics
Quadratic Equations and Inequalities
Question 123
Question 123 of 157
Medium
MCQ
Let [t] denote the greatest integer \[ \le \] t. Then the equation in x, [x]2 + 2[x+2] - 7 = 0 has :
A
no integral solution.
B
exactly two solutions.
C
exactly four integral solutions.
D
infinitely many solutions.
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Official solution
\[{[x]^2} + 2[x + 2] - 7 = 0\] \[ \Rightarrow \] \[{[x]^2} + 2[x] + 4 - 7 = 0\] Using the property [x + n] = [x] + n ; n \[ \in \] I \[ \Rightarrow \] \[{[x]^2} + 2[x] - 3 = 0\] let [x] = y
y
2
+
3
y
−
y
−
3
=
0
{y^2} + 3y - y - 3 = 0
y
2
+
3
y
−
y
−
3
=
0
\[ \Rightarrow \]
(
y
−
1
)
(
y
+
3
)
=
0
(y - 1)(y + 3) = 0
(
y
−
1
)
(
y
+
3
)
=
0
\[[x] = 1\,or\,[x] = - 3\] \[ \therefore \] \[x \in \left[ {1,2} \right)\,\& \, \in \left[ { - 3, - 2} \right)\]
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