The probability, that in a randomly selected 3-digit number at least two digits are odd, i…

Question

The probability, that in a randomly selected 3-digit number at least two digits are odd, is :

Accepted Answer

At least two digits are odd = exactly two digits are odd + exactly there 3 digits
are odd

For exactly three digits are odd

For exactly two digits odd :

If 0 is used then $: 2 	imes 5 	imes 5=50$

If 0 is not used then : ${ }^3 \mathrm{C}_1 	imes 4 	imes 5 	imes 5=300$

Required Probability $=\frac{475}{900}=\frac{19}{36}$

Solutions · 1