Let S be the sample space of all five digit numbers. It p is the probability that a randomly selected number from S, is a multiple of 7 but not divisible by 5 , then 9p is equal to :
Solutions · 1
Official solution
Among the 5 digit numbers,
First number divisible by 7 is 10003 and last is 99995.
\[\Rightarrow\] Number of numbers divisible by 7.
\[ = {{99995 - 10003} \over 7} + 1\]
=12857
First number divisible by 35 is 10010 and last is 99995.
\[\Rightarrow\] Number of numbers divisible by 35
\[ = {{99995 - 10010} \over {35}} + 1\]
=2572
Hence number of number divisible by 7 but not by 5
=12857−2572=10285
\[9P. = {{10285} \over {90000}} \times 9\]
=1.0285