Question 379 of 417EasyMCQ
A random variable X has the following probability distribution :
X
0
1
2
3
4
P(X)
k
2k
4k
6k
8k
The value of P(1
Solutions · 1
Official solution
\[\because\] x is a random variable
\[\therefore\] k+2k+4k+6k+8k=1
\[\therefore\] \[k = {1 \over {21}}\] Answer the question to unlock