Official solution
n(S) = 36
possible ordered pair :
(1, 1), (1, 2), (1, 3), (1, 5), (1, 7),
(2, 1), (2, 2), (2, 3), (2, 5),
(3, 1), (3, 2), (3, 3), (3, 5),
(5, 1), (5, 2), (5, 3),
(7, 1)
Number of favourable outcomes = 17
Probability = \[{{17} \over {36}}\]