A dice is thrown two times and the sum of the scores appearing on the die is observed to b…

Question

A dice is thrown two times and the sum of the
scores appearing on the die is observed to be
a multiple of 4. Then the conditional probability
that the score 4 has appeared atleast once is :

Accepted Answer

Let A is the event for getting score a multiple
of 4.

So, A = { (1, 3), (3, 1), (2, 2), (2, 6), (6, 2),
(3, 5), (5, 3), (4, 4), (6, 6) } = 09

n(A) = 9

B : Score of 4 has appeared at least once.

B = {(4, 4)}

So, Required probability = $${1 \over 9}$$

Solutions · 1