Official solution
\[P\left( {{A \over B}} \right) = {{P\left( {A \cap B} \right)} \over {P\left( B \right)}}\]
As A \[ \subset \] B,
then P(A\[ \cap \]B) = P(A)
\[ \therefore \] \[P\left( {{A \over B}} \right) = {{P\left( A \right)} \over {P\left( B \right)}}\]
As P(B) \[ \le \] 1
\[ \therefore \] \[{{P\left( A \right)} \over {P\left( B \right)}}\] \[ \ge \] P(A)